作者:
MyPower
,
2023-04-24 20:55:50
,
所有人可见
,
阅读 14
#include <bits/stdc++.h>
using namespace std;
const int N = 100010;
int p[N], siz[N];
int find(int x)
{
if(p[x] != x) p[x] = find(p[x]);
return p[x];
}
int main()
{
int n, m;
scanf("%d%d", &n, &m);
for(int i = 0; i < n; i ++)
{
p[i] = i;
siz[i] = 1;
}
while(m --)
{
char op[5];
int a, b;
scanf("%s", op);
if(op[0] == 'C')
{
scanf("%d%d", &a, &b);
if(find(a) == find(b)) continue;
siz[find(b)] += siz[find(a)];//在合并两个树时, 先让b树加上a树的点的数量
p[find(a)] = find(b);
}
else if(op[1] == '1')
{
scanf("%d%d", &a, &b);
if(find(a) == find(b)) cout << "Yes" << endl;
else cout << "No" << endl;
}
else
{
scanf("%d", &a);
cout << siz[find(a)] << endl;
}
}
return 0;
}