自己写的

#include <bits/stdc++.h>

using namespace std;

typedef pair<string, string> PII;

const int N = 1010;

int n;
vector<PII> res;
bool mod[N];

int main()
{
    scanf("%d", &n);

    for (int i = 0; i < n; i ++ )
    {
        string a, b;
        cin >> a >> b;
        res.push_back({a, b});
    }

    for (size_t i = 0; i < res.size(); i ++ )
    {

        string k = res[i].second;
        string re;
        for (int j = 0; j < k.size(); j ++ )
        {
            if (k[j] == '1') re += '@', mod[i] = true;
            else if (k[j] == '0') re += '%', mod[i] = true;
            else if (k[j] == 'l') re += 'L', mod[i] = true;
            else if (k[j] == 'O') re += 'o', mod[i] = true;
            else re += k[j];
        }
        res[i].second = re;
    }

    int cnt = 0;
    for (int i = 0; i < n; i ++ )
        if (mod[i]) cnt ++ ;

    if (cnt == 0) 
    {
        if (n == 1) printf("There is 1 account and no account is modified");
        else printf("There are %d accounts and no account is modified", n);
    }
    else
    {
        cout << cnt << endl;
        for (int i = 0; i < n; i ++ )
            if (mod[i])
                cout << res[i].first << ' ' << res[i].second << endl;
    }
    return 0;
}

y总优美代码

题解


#include <iostream>

using namespace std;

const int N = 1010;

string name[N], pwd[N];

string change(string str)
{
    string res;

    for (auto c : str)
        if(c == '1')    res += '@';
        else if(c == '0')    res += '%';
        else if(c == 'l')    res += 'L';
        else if(c == 'O')    res += 'o';
        else res += c;

    return res;
}

int main()
{
    int n;
    cin >> n;

    int m = 0;
    for(int i = 0; i < n; i ++ )//从前往后读入每个同学的信息
    {
        string cur_name, cur_pwd;
        cin >> cur_name >> cur_pwd;//读入当前用户名和当前密码

        //判断是否修改密码（判断和修改可同时放在一个函数中）→利用函数修改掉密码中所有有歧义的字符
        string changed_pwd = change(cur_pwd);//求出更新后密码

        if(changed_pwd != cur_pwd)//如果密码被修改了
        {
            name[m] = cur_name;
            pwd[m] = changed_pwd;
            m++;
        }
    }

    //  !m  <=> m == 0
    if(!m)//如果密码没被修改过
    {
        if(n == 1) puts("There is 1 account and no account is modified");
        else printf("There are %d accounts and no account is modified\n", n);
    }
    else//密码被修改过，输出名字及密码
    {
        cout << m << endl;
        for (int i = 0; i < m; i ++ ) cout << name[i] << ' ' << pwd[i] << endl;
    }

    return 0;
}