百家姓（2）

嘿嘿，百家姓第二篇来了，今天多更新好像是56个姓吧。
先上代码：

#include<bits/stdc++.h>

using namespace std;
string a;
int main() {
    cin >> a;
    string b = "zeng";
    string c = "jiang";
    string d = "zhou";
    string e = "yan";
    string f = "yao";
    string g = "xu";
    string h = "zhu";
    string i = "huang";
    string j = "meng";
    string k = "pan";
    string::size_type idx;
    idx = a.find(b);
    if (idx == string::npos )
        cout << "";

    string::size_type idx_b;
    idx = a.find(c);
    if (idx_b == string::npos )
        cout << "";

    string::size_type idx_c;
    idx = a.find(d);
    if (idx_c == string::npos )
        cout << "";

    string::size_type idx_d;
    idx = a.find(e);
    if (idx_d == string::npos )
        cout << "";

    string::size_type idx_e;
    idx = a.find(f);
    if (idx_e == string::npos )
        cout << "";
    string::size_type idx_f;
    idx = a.find(g);
    if (idx_e == string::npos )
        cout << "";
    string::size_type idx_g;
    idx = a.find(h);
    if (idx_e == string::npos )
        cout << "";
    string::size_type idx_h;
    idx = a.find(i);
    if (idx_e == string::npos )
        cout << "";
    string::size_type idx_i;
    idx = a.find(j);
    if (idx_e == string::npos )
        cout << "";
    string::size_type idx_j;
    idx = a.find(k);
    if (idx_e == string::npos )
        cout << "";
    else cout << "存在" << endl;

    if (a >= "a" && a <= "z")
        a[0] -= 32;
    cout << a << endl;

}