//二进制 
#include<bits/stdc++.h>
using namespace std;
const int N=1e5+10;
int n,m;
int a[N],b[N];
int main(){
    int c=5;
    cout<<(5^6)<<endl;  //3
    cout<<(5&6)<<endl;  //4
    cout<<(5|6)<<endl;  //7
    cout<<(~5)<<endl;   //-6
    cout<<(-1/4)<<endl; //0
    cout<<(1<<4)<<endl; //16
    cout<<(13>>2)<<endl; //3
    cout<<((-1)>>2)<<endl; //-1
    cout<<(8 & 7)<<endl;   //判断 a是否是2^k 
    cout<<(6&-6)<<' '<<(8 & -8)<<' '<<(7 & -7)<<endl; //2,8,1,取该数最后一个 1 
    cout<<(a&~(1<<b))<<endl;//把第 b位变为 0 
    cout<<(23|(1<<b))<<endl;//把第 b位变为 1 
    cout<<((77>>b)&1)<<endl;
    cout<<((31>>b)&1)<<endl;//判断第 b位是不是 1 
    cout<<(31^(1<<4))<<endl;//把第 b位取反 
    return 0;
}