Go 语言实现next_permutation

func reverse(nums[]int,l,r int){
    for l<r{
        nums[l],nums[r]=nums[r],nums[l]
        l++
        r--
    }
}
func next_permutation(nums[]int)bool{
    right:=len(nums)-1
    for right>0&&nums[right]<=nums[right-1]{
        right--
    }
    if right==0{
        return false
    }
    process:=right-1
    for i:=len(nums)-1;i>privot;i--{
        if nums[i]>nums[privot]{
            nums[privot],nums[i]=nums[i],nums[privot]
            break
        }
    }
    reverse(nums,privot+1,len(nums)-1)
    return true
}