由苟弱cht所做(刚看到有个算法组的所以写了个语法组的)

题目列表：

1, 2, 3, 604, 605, 606, 607, 608, 609, 610, 611, 612, 613, 614, 615, 616, 617, 618, 653, 654, 655, 656, 657, 658, 659, 660, 661, 662, 663, 664, 665, 666, 667, 668, 669, 670, 671, 672, 708, 709, 710, 711, 712, 713, 714, 715, 716, 717, 718, 719, 720, 721, 722, 723, 724, 726, 727, 737, 738, 739, 740, 741, 742, 743, 744, 745, 746, 747, 748, 749, 750, 751, 752, 753, 754, 755, 756, 760, 761, 762, 763, 764, 765, 766, 767, 768, 769, 770, 771, 772, 773, 774, 775, 776, 777, 778, 779

1. A + B

#include<iostream>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    cout<<a+b;
}

2.01背包问题

#include<iostream>
using namespace std;
const int N = 1010;
int n,m,v[N],w[N],f[N];
int main()
{
    cin >> n >> m;
    for (int i = 1; i <= n; i ++ ) cin >> v[i] >> w[i];
    for (int i = 1; i <= n; i ++ )
        for (int j = m; j >= v[i]; j -- )
            f[j] = max(f[j], f[j - v[i]] + w[i]);
    cout << f[m];
}

3.完全背包问题

#include<iostream>
using namespace std;
const int N = 1010;
int n,m,v[N],w[N],f[N];
int main()
{
    cin >> n >> m;
    for (int i = 1; i <= n; i ++ ) cin >> v[i] >> w[i];
    for (int i = 1; i <= n; i ++ )
        for (int j = v[i]; j <= m; j ++ )
            f[j] = max(f[j], f[j - v[i]] + w[i]);
    cout << f[m];
}

604.圆的面积

#include<iostream>
using namespace std;
int main()
{
    double a;
    cin >> a;
    printf("A=%.4lf",r*r*3.14159);
}

605.简单乘积

#include<iostream>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    printf("PROD = %d",a*b);
}

606.平均数1

#include<iostream>
using namespace std;
int main()
{
    double a, b;
    cin >> a >> b;
    printf("MEDIA = %.5lf", (a * 3.5 + b * 7.5) / 11);
}

607.平均数2

#include<iostream>
using namespace std;
int main()
{
    double a, b, c;
    cin >> a >> b >> c;
    printf("MEDIA = %.1lf", (a * 2 + b * 3 + c * 5) / 10);
}

608.差

#include<iostream>
using namespace std;
int main()
{
    int a, b, c, d;
    cin >> a >> b >> c >> d;
    printf("DIFERENCA = %d", a * b - c * d);
}

609.工资

#include<iostream>
using namespace std;
int main()
{
    int a,b
    double x;
    cin >> a >> b >> x;
    printf("NUMBER = %d\n", a);
    printf("SALARY = U$ %.2f", b * c);
}

610.工资和奖金

#include<iostream>
using namespace std;
int main()
{
    string a;
    double b, c;
    cin >> a >> b >> c;
    printf("TOTAL = R$ %.2f", a, b + c * 0.15);
}

611.简单计算

#include<iostream>
using namespace std;
int main()
{
    int a1, b1, a2, b2;
    double c1, c2;
    cin >> a1 >> b1 >> c1 >> a2 >> b2 >> c2;
    printf("VALOR A PAGAR: R$ %.2lf", b1 * c1 + b2 * c2);
}

612.球的体积

#include<iostream>
using namespace std;
int main()
{
    double a;
    cin >> a;
    printf("VOLUME = %.3lf\n", 4 / 3.0 * 3.14159 * a * a * a);
}

613.面积

#include<iostream>
using namespace std;
int main()
{
    double a, b, c;
    cin >> a >> b >> c;
    printf("TRIANGULO: %.3lf\nCIRCULO: %.3lf\nTRAPEZIO: %.3lf\nQUADRADO: %.3lf\nRETANGULO: %.3lf", a * c / 2,3.14159 * c * c, (a + b) * c / 2, b * b, a * b);
}

614.最大值

#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
    int a[3];
    cin >> a[0] >> a[1] >> a[2];
    sort(a,a + 3);
    cout << a[2]<<" eh o maior";
}

615.油耗

#include <iostream>
using namespace std;
int main()
{
    int s;
    double o;
    cin >> s >> o;
    printf("%.3lf km/l", s / o);
}

616.两点间的距离

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    double x1, y1, x2, y2;
    cin >> x1 >> y1 >> x2 >> y2;
    double x = x1 - x2,y = y1 - y2;
    printf("%.4lf", sqrt(dx * dx + dy * dy));
} 

617.距离

#include <iostream>
using namespace std;
int main()
{
    int a;
    cin >> a;
    printf("%d minutos", a * 2);
}

618.燃料油耗

#include <iostream>
using namespace std;
int main()
{
    double a, b;
    cin >> a >> b;
    printf("%.3lf", a * b / 12);
}

653.钞票

#include <iostream>
using namespace std;
int main()
{
    int n, a[7] = {100, 50, 20, 10, 5, 2, 1};
    cin >> n;
    cout << n << endl;
    for (int i = 0; i < 7; i ++ )
    {
        printf("%d nota(s) de R$ %d,00\n", n / a[i], a[i]);
        n %= a[i];
    }
}

654.时间转换

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    printf("%d:%d:%d", n / 3600, n % 3600 / 60, n % 60);
}

655.天数转换

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    printf("%d ano(s)\n%d mes(es)\n%d dia(s)", n / 365, n % 365 / 30, n % 365 % 30);
}

656.钞票与硬币（这个是我最不希望碰到的题）

#include <iostream>
using namespace std;
int main()
{
    double m;
    cin >> m;
    int n = m * 100,a[] = {100, 50, 20, 10, 5, 2},b[] = {100, 50, 25, 10, 5, 1};
    puts("NOTAS:");
    for (int i = 0; i < 6; i ++ )
    {
        printf("%d nota(s) de R$ %.2lf\n", n / (a[i] * 100), (double)a[i]);
        n %= a[i] * 100;
    }
    puts("MOEDAS:");
    for (int i = 0; i < 6; i ++ )
    {
        printf("%d moeda(s) de R$ %.2lf\n", n / b[i], b[i] / 100.0);
        n %= b[i];
    }
}

657.选择练习1(记住范围！！！，别写错！！！！)

#include <iostream>
using namespace std;
int main()
{
    int a, b, c, d;
    cin >> a >> b >> c >> d;
    if (b > c && d > a && c + d > a + b && c > 0 && d > 0 && a % 2 == 0) cout << "Valores aceitos";
    else cout << "Valores nao aceitos";
}

658.一元二次方程公式

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    double a, b, c;
    cin >> a >> b >> c;
    double d = b * b - 4 * a * c;
    if (d < 0 || a == 0) cout << "Impossivel calcular" << endl;
    else
    {
        double x = (-b + sqrt(d)) / a / 2;
        double y = (-b - sqrt(d)) / a / 2;
        printf("R1 = %.5lf\n", x);
        printf("R2 = %.5lf\n", y);
    }
}

659.区间（水题+难写）

#include <iostream>
using namespace std;
int main()
{
    double x;
    cin >> x;
    if (x >= 0)
        if (x <= 25) puts("Intervalo [0,25]");
        else if (x <= 50) puts("Intervalo (25,50]");
        else if (x <= 75) puts("Intervalo (50,75]");
        else if (x <= 100) puts("Intervalo (75,100]");
        else puts("Fora de intervalo");
    else puts("Fora de intervalo");
}

660.零食（记住，遇到这种题不是啥好事）

#include <iostream>
using namespace std;
int main()
{
    int x, y;
    cin >> x >> y;
    if (x == 1) printf("Total: R$ %.2lf", y * 4.0);
    else if (x == 2) printf("Total: R$ %.2lf", y * 4.5);
    else if (x == 3) printf("Total: R$ %.2lf", y * 5.0);
    else if (x == 4) printf("Total: R$ %.2lf", y * 2.0);
    else printf("Total: R$ %.2lf", y * 1.5);
}

661.平均数3(此题超烦)

#include <iostream>
using namespace std;
int main()
{
    double a, b, c, d;
    cin >> a >> b>> c >> d;
    double x = (a * 2 + b * 3 + c * 4 + d * 1) / 10;
    printf("Media: %.1lf\n", x);
    if (x >= 7) puts("Aluno aprovado.");
    else if (x < 5) puts("Aluno reprovado.");
    else
    {
        puts("Aluno em exame.");
        double y;
        cin >> y;
        printf("Nota do exame: %.1lf\n", y);
        double z = (x + y) / 2;
        if (z >= 5) puts("Aluno aprovado.");
        else puts("Aluno reprovado.");
        printf("Media final: %.1lf", z);
    }
}