核心:将字符存进string数组中,输出即可

getline(cin, str)的复习

满分

核心: vector的erase的使用, 传参是vector.begin()

/**
题意: 矩阵存储字符,通过words,一行打印字符

难点: 存储数据 vector<string> a;
先将字母抽离到vector<string> b中, 再循环b输出每一个字符
*/
#include <iostream>
#include <cstring>
#include <vector>
using namespace std;

vector<string> alp[30], word;

int main()
{
    string str, s;
    for(int i = 0; i < 26; i++){
        for(int j = 0; j < 7; j++)
        {
            getline(cin, str);
            alp[i].push_back(str);
        }
    }
    getline(cin, s);
    // erase是索引,必须使用s.begin(), 而不是s[0]
    while (!isupper(s[0])) s.erase(s.begin());
    int pos = 0, t = 0;
    while (t < s.size())
    {
        while (isupper(s[t])) t++;
        word.push_back(s.substr(pos, t - pos));
        while (!isupper(s[t])) t++;
        pos = t;
    }
    for(int i = 0; i < word.size(); i++)
    {
        if (i) printf("\n");
        string sw = word[i];
        for(int k = 0; k < 7; k++)
        {
            string tmp;
            for(int j = 0; j < sw.size(); j++)
            {
                if (j != 0) tmp += " ";
                tmp += alp[sw[j] - 'A'][k];
            }
            cout << tmp << '\n';
        }

    }
}

13分 代码 两个格式错误, 一个内存超限

方法一(较好):

#include <iostream>
#include <cstring>

using namespace std;
const int N = 200;
string l[N], res[N];

int main()
{
    string str;
    for(int i = 0; i < 182; i++)
    {
        getline(cin , str);
        l[i] = str;
    }
    getline(cin, str);
    int len = str.length();
    int cnt = 7;
    bool flag = true;
    int f = 0;
    for(int i = 0; i < len; i++)
    {
        int x = str[i] - 'A';
        x *= 7;
        if (str[i] >= 'A' && str[i] <= 'Z')
        {
            int idx = 0;
            for(int j = cnt - 7; j < cnt; j++)
            {
                if (flag) flag = false;
                else if (!flag && f >= 7) res[j] += " ";
                res[j] += l[x + idx];
                idx++;
                f++;
            }
        }else
        {
            if (!flag && i != len - 1)
            {
                cnt++;
                cnt += 7;
            }
            f = 0;
            flag = true;
        }
    }
    for(int i = 0; i < cnt; i++)
    {
        cout << res[i] << '\n';
    }
}

1分 3个格式错误, 一个运行错误

方法二(vector设置大一些即可)

#include <iostream>
#include <cstring>
#include <vector>
using namespace std;

const int N = 190;
string arr[N];
vector<string> vc[N *2];
int cnt = 0, idx = 0;
bool check(char s)
{
    if (s >= 'A' && s <= 'Z') return true;
    else return false;
}
void getres(char s)
{
    cnt = idx;
    int x = s - 'A';
    x = x * 7 + 1;
    for(int i = x; i <= x + 6; i++)
    {
        vc[cnt++].push_back(arr[i] + " ");
    }
}
int main()
{
    string str;
    for(int i = 1; i <= 182; i++)
    {
        getline(cin, str);
        arr[i] = str;
    }
    getline(cin, str);
    for(int i = 0; i < str.size(); i++)
    {
        if (check(str[i]))
        {
            break;
        }else cnt++;
    }
    str = str.substr(cnt, str.size() - cnt);
    string res;
    int j;
    for(int i = 0; i < str.size(); i++)
    {
        res += str[i];
        if (!check(str[i]))
        {
            j = i + 1;
            while (!check(str[j])) j++;
        }
    }
    for(int i = 0; i < res.size(); i++)
    {
        if (check(res[i]))
        {
            getres(res[i]);
        }else {
            idx = cnt;
            idx ++;
        }
    }
    int len = max(cnt, idx);
    for(int i = 0; i < len; i++)
    {
        if (vc[i].size() > 0)
        {
            for(j = 0; j < vc[i].size(); j++)
            {
                if (j == vc[i].size() - 1) vc[i][j].pop_back();
                printf("%s", vc[i][j].c_str());
            }
        }

        printf("\n");
    }
}

满分, 第一次写的代码

方法三

#include <iostream>
#include <cstring>
#include <vector>
using namespace std;

const int N = 200;
const int M = 3000;
vector<string> res[N];
// 输入的时候段错误了
vector<string> vc[M];
int n1, cnt = 0;
void out_it(int x)
{
    int len = x * 7;
    int beg = len - 6;
    // 每一列行向输出
    n1 = cnt;
    for(int i = beg; i <= len; i++)
    {
        vc[n1].push_back(res[i][0]);
        string s = " ";
        vc[n1].push_back(s);
        n1++;
    }

    // 输出一列空格

}
void out_vc()
{
    cnt = n1;
    cnt++;
}

bool check(char a)
{
    if (a >= 'A' && a <= 'Z')
    {
        return true;
    }
    return false;
}
int main()
{
    int m = 26, x = 5, y = 7;

    for(int i = 1; i <= 182; i++)
    {
        string sstr;
        getline(cin, sstr);
        res[i].push_back(sstr);
    }


    string str;
    //getchar(); // 吸收换行, 在scanf或cin 之后,需要吸收换行
    getline(cin , str);
    for(int i = 0; i < str.size(); i++)
    {
        // 为啥下划线会进去???
        if (check(str[i]))
        {
            int a = str[i] - 'A' + 1;
            // 输出
            out_it(a);
        }else {
            // 输入一行空格
            out_vc();
        }
    }
    bool flag = false;
    for(int i = 0; i < n1; i++)
    {
        //printf("%d\n", vc[i].size());
        if (vc[i].size() == 0) {
            if (flag) printf("\n");
            continue;
        }
        for(int j = 0; j < vc[i].size() - 1; j++)
        {
            flag = true;
            cout << vc[i][j];
        }
        if (vc[i].size() == 0) cout << '\n';
        if (i != n1 - 1) cout << '\n';
        //cout << '\n';

    }
}