十进制转换为二进制

#include <iostream>
using namespace std;
int main()
{
    int a[10] = {0};
    int n = 2022, count = 0;
    while (n)
    {
        a[count ++] = n % 2;
        n /= 2;
    }

    for (int i = count - 1; i >= 0; i --) cout << a[i];

    cout << endl;

    for (int i = 31; i >= 0; i --)
    {
        cout << (2022 >> i & 1);

    }


}