//各个位的字符串转成数字，将数字都加起来
//将数字转化为字符串，将各个位的字符与字典对应，然后输出
#include <bits/stdc++.h> 
using namespace std;

string str;
int sum = 0;
string str1;
int main(){
    cin>>str;
    for(int i = 0;i < str.size();i++){
        sum += str[i]-48;

    }
    str1 = to_string(sum);
    for(int i=0;i<str1.size();i++){
        if(str1[i]=='0')cout<<"zero"<<" ";//改进：用一个string存这些可能的映射会减少更多代码
        else if(str1[i]=='1')cout<<"one"<<" ";
        else if(str1[i]=='2')cout<<"two"<<" ";
        else if(str1[i]=='3')cout<<"three"<<" ";
        else if(str1[i]=='4')cout<<"four"<<" ";
        else if(str1[i]=='5')cout<<"five"<<" ";
        else if(str1[i]=='6')cout<<"six"<<" ";
        else if(str1[i]=='7')cout<<"seven"<<" ";
        else if(str1[i]=='8')cout<<"eight"<<" ";
        else if(str1[i]=='9')cout<<"nine"<<" ";

    }

    return 0;
}