spfa最短路
作者:
Oct_9
,
2024-04-24 13:16:08
,
所有人可见
,
阅读 11
#include <iostream>
#include <algorithm>
#include <cstring>
#include <queue>
using namespace std;
typedef pair<int, int> PII;
const int N = 100010;
int n, m;
int h[N], w[N], ne[N], e[N], idx;
int dist[N];
bool st[N];
void add(int a, int b, int c)
{
e[idx] = b;
w[idx] = c;
ne[idx] = h[a];
h[a] = idx ++;
}
int spfa()
{
memset(dist, 0x3f, sizeof dist);
dist[1] = 0;
queue<int> q;
q.push(1);
st[1] = true;
while (q.size())
{
int t = q.front();
q.pop();
st[t] = false;
for (int i = h[t]; i != -1; i = ne[i])
{
int j = e[i];
if (dist[j] > dist[t] + w[i])
{
dist[j] = dist[t] + w[i];
if (!st[j])
{
q.push(j);
st[j] = true; // 一个点只能在队列里面存在一次
}
}
}
}
return dist[n];
}
int main()
{
scanf("%d%d", &n, &m);
memset(h, -1, sizeof h);
while (m --)
{
int a, b, c;
scanf("%d%d%d", &a, &b, &c);
add(a, b, c);
}
int t = spfa();
if (t == 0x3f3f3f3f) puts("impossible");
else printf("%d", t);
return 0;
}