一文学会在Markdown中编辑数学符号与公式
数学识别软件
(1.2234)
[1234]
{1234}
|1234|
∥1234∥
(1234)
[1234]
{1234}
|1234|
∥1234∥
(1a1a21⋯an11a2a22⋯an2⋮⋮⋮⋱⋮1ama2m⋯anm)
系统状态方程 ˙x=Ax 的解为
x=eAx(0)
0.98365≈0.0006
1.02365≈1377.4
v+w=0Given−w=−w+0additive identity−w+0=−w+(v+w)equations (1) and (2)
√37=√732−1122=√732122⋅732−1732=√732122√732−1732=7312√1−1732≈7312(1−12⋅732)