*    
   ***   
  *****  
 ******* 
*********
 ******* 
  *****  
   ***   
    *   

基数菱形的打印
1.中心点坐标(n/2,n/2)
2.计算曼哈段距离阈值：n/2
3.任意这<=个距离的位置均为 *

#include <iostream>

using namespace std;

int main()
{
    int n;
    cin >> n;

    int cx = n / 2, cy = n / 2;

    for (int i = 0; i < n; i ++ )
    {
        for (int j = 0; j < n; j ++ )
            if (abs(i - cx) + abs(j - cy) <= n / 2)
                cout << '*';
            else cout << ' ';
        cout << endl;
    }

    return 0;
}