/输入年月日,计算该天是本年的第N天(1<=年<=3000,1<=月<=12,1<=日<=31)，如输入数据为2017 12 24三个参数，输出结果为“N=358”
/

#include<iostream>
using namespace std;

const int months[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};

int is_leap(int year){
     if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
      return 1;
     return 0;
}

int get_days(int y,int m){
    if(m==2) return months[m]+is_leap(y);
    return months[m];
}

int calculateDayOfYear(int y,int m,int d){
     int n = 0;
     for(int i=1;i<m;i++)
          n+=get_days(y,i);
     for(int i=1;i<=d;i++)
          n++;
    return n;
}

int main(){
     int y,m,d;
     cin>>y>>m>>d;
     printf("N=%d",calculateDayOfYear(y,m,d));
    return 0;
}