floyd
作者:
ysc
,
2021-07-29 21:49:43
,
所有人可见
,
阅读 240
#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 210, INF = 1e9;
int d[N][N];
int n, m, Q;
void floyd()
{
for ( int k = 1; k <= n; k ++ )
for ( int i = 1; i <= n; i ++ )
for ( int j = 1; j <= n; j ++ )
d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
}
int main()
{
cin >> n >> m >> Q;
for ( int i = 1; i <= n; i ++ )
for ( int j = 1; j <= n; j ++ )
if ( i == j ) d[i][j] = 0;
else d[i][j] = INF;
while ( m -- )
{
int a, b, w;
cin >> a >> b >> w;
d[a][b] = min(d[a][b], w);
}
floyd();
while ( Q -- )
{
int a, b;
cin >> a >> b;
if ( d[a][b] > INF / 2 ) puts("impossible");
else cout << d[a][b] << endl;
}
return 0;
}