题目描述

简单的进制转换

C++ 代码

#include <iostream>
#include <algorithm>
using namespace std;
string itoa(int n)
{
    string ans;
    do
    {
        if (n % 13 < 10) ans += n % 13 + '0';
        else ans += n % 13 - 10 + 'A';
        n /= 13;
    } while(n);
    reverse(ans.begin(), ans.end());
    return ans;
}
int main()
{
    int a[3];
    string s[3];
    cin >> a[0] >> a[1] >> a[2];
    cout << "#";
    for (int i = 0; i < 3; i ++)
    {
        s[i] = itoa(a[i]);
        while (s[i].size() < 2) s[i] = "0" + s[i];
        cout << s[i];
    }
}