题目描述

用double数组n来记录每一位上的数值，模拟一下就好了

C++ 代码

#include <iostream>
using namespace std;
const int N = 1010;
double n[N];
int main()
{
    for (int i = 0; i < 2; i ++)
    {
        int k;
        cin >> k;
        for (int j = 0; j < k; j ++)
        {
            int a;
            double b;
            cin >> a >> b;
            n[a] += b;
        }
    }
    int k = 0;
    for (int i = 0; i < N; i ++)
        if (n[i] != 0) k ++;
    cout << k << " ";
    for (int i = N - 1; i >= 0; i --)
        if (n[i] != 0) printf("%d %.1lf ", i, n[i]);
}