思路

• 如果是数字：就从字符串中读入，十位 names[v / 13 + 12]，个位 names[v % 13]

  • 如果是一位数，就直接 names[v % 13]

  • 如果是两位数，先判断是不是整十的，整十的只输出十位。

  • 如果是英文：遍历一遍 names[] 找同样的词

    • 小于13：就返回i

    • 不然它应该是十位，返回 (i - 12) * 13

知识点

stringsteam ssin (line) 从字符串里读东西出来，每次读一整行

记得把回车干掉，用 getchar()

#include<iostream>
#include<algorithm>
#include<sstream> 

using namespace std;

int main()
{
    int n;
    cin >> n;
    getchar();

    while(n -- )
    {
        string line;
        getline(cin, line);

        stringstream ssin(line);

        int v;
        ssin >> v ;
        cout << v << endl;
    }

    return 0;
}

y总优雅代码

#include<iostream>
#include<algorithm>
#include<sstream>

using namespace std;

char names[][5] = {
    "tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec",
    "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou",
};

int get(string word)
{
    for (int i = 0; i < 25; i ++ )
        if (word == names[i])
        {
            if (i < 13) return i;
            else return (i - 12) * 13;
        }
    return 0;
}

int main()
{
    int n;
    cin >> n;
    getchar();

    while(n -- )
    {
        string line;
        getline(cin, line);

        stringstream ssin(line);  // 从字符串里读

        if (line[0] <= '9') // 说明是个数字
        {
            int v;
            ssin >> v;
            if (v < 13) cout << names[v % 13] << endl;
            else
            {
                if (v % 13 == 0) cout << names[v / 13 + 12] << endl;
                else cout << names[v / 13 + 12] << ' ' << names[v % 13] << endl;
            }
        }
        else
        {
            int res = 0;
            string word;
            while(ssin >> word) res += get(word);
            cout << res << endl;
        }
    }

    return 0;
}

我被自己的弱智蠢哭了。真正见识到，什么叫弱智，就是我。

#include<iostream>
#include<algorithm>
#include<sstream>

using namespace std;

char ge[][5] = {"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};
char shi[][5] = {"", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};


int number(string str)
{
    int res = 0;
    for (int i = 0; i < str.size(); i ++ )
    {
        res = res * 10 + str[i] - '0';
    }
    return res;
}

int get(string str)
{
    for (int i = 0; i < 13; i ++ )
    {
        if (str == shi[i]) return i;
    }
    return 0;
}


int main()
{
    int n;
    cin >> n;
    getchar();

    while(n -- )
    {
        string str;
        getline (cin , str);

        stringstream ssin(str);        
        if (str[0] <= '9')
        {
            int num = number(str);
            if (num == 0) cout << "tret" << endl;
            else if (num % 13 == 0 && num != 0) cout << shi[num / 13] << endl;
            else if (num < 13) cout << ge[num % 13] << endl;
            else cout << shi[num / 13] << ' ' << ge[num % 13] << endl;
        }
        else 
        {
            string r1, r2;
            int g, s;
            if (str.size() > 4)
            {
                for (int i = 0; i < 3; i ++ ) r1 += str[i];

                for (int i = 0; i < 13; i ++ )
                    if(r1 == shi[i]) s = i ;


                for (int i = 4; i < 7; i ++ ) r2 += str[i];

                for (int i = 0; i < 13; i ++ )
                    if(r2 == ge[i]) g = i;


                cout << s * 13 + g << endl;
            }
            else
            {
                for (int i = 0; i < 3; i ++ ) r1 += str[i];
                //cout << r1 <<endl;

                for (int i = 0; i < 13; i ++ )
                {
                    if (r1[0] == 't' && r1[1] == 'r')
                    {
                        cout << "0" << endl;
                        break;
                    }
                    else
                    {
                        if (r1 == shi[i]) cout << i * 13 << endl;
                        if (r1 == ge[i]) cout << i << endl ;
                    }


                }

            }

        }

    }

    return 0;
}