题目描述

In an alien language, surprisingly they also use english lowercase letters, but possibly in a different order. The order of the alphabet is some permutation of lowercase letters.

Given a sequence of words written in the alien language, and the order of the alphabet, return true if and only if the given words are sorted lexicographicaly in this alien language.

样例

Example 1:

Input: words = ["hello","leetcode"], order = "hlabcdefgijkmnopqrstuvwxyz"
Output: true
Explanation: As 'h' comes before 'l' in this language, then the sequence is sorted.
Example 2:

Input: words = ["word","world","row"], order = "worldabcefghijkmnpqstuvxyz"
Output: false
Explanation: As 'd' comes after 'l' in this language, then words[0] > words[1], hence the sequence is unsorted.
Example 3:

Input: words = ["apple","app"], order = "abcdefghijklmnopqrstuvwxyz"
Output: false
Explanation: The first three characters "app" match, and the second string is shorter (in size.) According to lexicographical rules "apple" > "app", because 'l' > '∅', where '∅' is defined as the blank character which is less than any other character (More info).

算法1

(Hashmap) $O(n)$

按照dict的字母顺序将数组中的word转换成数字，然后比较数组中的word，如果不满足升序即输出false

时间复杂度

遍历dict，O（1），遍历数组O（n）
需要额外的vector或者hashmap存储26个字母，O（1）

参考文献

C++ 代码

class Solution {
public:
    bool isAlienSorted(vector<string>& words, string order) {
        vector<int> m(256);
        for(int i=0;i<order.size();i++)
            m[order[i]]=i;
        for(int i=0;i<words.size();i++)
        {
            for(int j=0;j<words[i].size();j++)
            {
                words[i][j]=m[words[i][j]];                
            }
            if(i>0 && words[i]<words[i-1]) return false;
        }
        return true;
    }
};