LeetCode 21. 合并两个有序链表
原题链接
简单
作者:
optimjie
,
2020-05-03 02:15:43
,
所有人可见
,
阅读 793
算法一:遍历
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(-1);
ListNode tail = dummy;
ListNode p1 = l1, p2 = l2;
while (p1 != null && p2 != null) {
int val = 0;
if (p1.val <= p2.val) {
val = p1.val;
p1 = p1.next;
} else {
val = p2.val;
p2 = p2.next;
}
ListNode tmp = new ListNode(val);
tail.next = tmp;
tail = tmp;
}
tail.next = p1 == null ? p2 : p1;
return dummy.next;
}
}
算法二:递归
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) return l2;
if (l2 == null) return l1;
if (l1.val <= l2.val) {
l1.next = mergeTwoLists(l1.next, l2);
return l1;
} else {
l2.next = mergeTwoLists(l1, l2.next);
return l2;
}
}
}