C++ 代码

# s[i][j] = a[i][j] + s[i-1][j] + s[i][j-1] - s[i-1][j-1]
#include <iostream>
using namespace std;

const int N = 1000+10;

int s[N][N];

int main() {

    int n, m, q;
    cin >> n >> m >> q;

    for (int i=1; i<=n; i++) {
        for (int j=1; j<=m; j++) {
            cin >> s[i][j]; // a[i][j]
            s[i][j] += s[i-1][j] + s[i][j-1] - s[i-1][j-1];
        }
    }

    int x1, y1, x2, y2;
    while (q --) {
        cin >> x1 >> y1 >> x2 >> y2;
        cout << s[x2][y2] - s[x2][y1-1] - s[x1-1][y2] + s[x1-1][y1-1] << endl;
    }

    return 0;
}