//对time进行反复加减，因为最后结果出现次数大于一半，所有最后留下来的就是所求结果

#include <iostream>

using namespace std;

int main()
{
    int i = 0;
    int j = 0;
    cin >> i >> j;
    long long result = 0;
    int time = 0;

    for(int n = 0 ; n < j; n++)
        for(int k = 0; k < i; k ++)
        {
            int temp = 0 ;
            cin >> temp;
            if(time == 0)
            {
                 result = temp;
                 time = 1;
                 continue;
            }

            if(result == temp)
            {
                time ++;
                continue;
            }else
            {
                time--;
                continue;
            }

        }
    cout << result <<endl;

    return 0 ;
}