AcWing 763. 循环相克令

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AcWing 763. 循环相克令原题链接简单

作者：

黄 , 2020-07-09 09:00:02 , 所有人可见 , 阅读 10080

183

84

用string的size之差表示player1赢的三种情况

#include <iostream>

using namespace std;

int main()
{
    int n;
    cin >> n;

    string x, y;
    while (n --)
    {
        cin >> x >> y;
        int a = x.size(), b = y.size();
        if (a - b == -1 || a - b == -2 || a - b == 3)
            cout << "Player1" << endl;
        else if (a == b)
            cout << "Tie" << endl;
        else cout << "Player2" << endl;
    }

    return 0;
}

54 评论

与或 2023-01-09 15:15

想法很妙但是有点取巧，可能还是用012分别表示变量，构造函数关系判断通用一点

张立杰 2023-07-09 16:32

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string a="Hunter",b="Bear",c="Gun";
    int t[3]={a.size()-c.size(),b.size()-a.size(),c.size()-b.size()};
    int n;
    string s1,s2;
    cin>>n;
    while(cin>>s1>>s2,n--)
    {
    int a=s1.size(),b=s2.size(),c=a-b;
    if(c==t[0]||c==t[1]||c==t[2])
    cout<<"Player1"<<endl;
    else if(!c)cout<<"Tie"<<endl;
    else cout<<"Player2"<<endl;
    }
    return 0;
}

meigumi 2022-11-07 16:18

while(1) printf(“666”);

木石石石_1 2023-01-18 20:58

牛哇！一行一个死循环（doge）

张立杰 2023-07-09 16:32

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string a="Hunter",b="Bear",c="Gun";
    int t[3]={a.size()-c.size(),b.size()-a.size(),c.size()-b.size()};
    int n;
    string s1,s2;
    cin>>n;
    while(cin>>s1>>s2,n--)
    {
    int a=s1.size(),b=s2.size(),c=a-b;
    if(c==t[0]||c==t[1]||c==t[2])
    cout<<"Player1"<<endl;
    else if(!c)cout<<"Tie"<<endl;
    else cout<<"Player2"<<endl;
    }
    return 0;
}

journey_3 3个月前

个人觉得如果看字符串长度判断的话，只能针对这个题。有没有一种通解办法，也可以适用类似猜拳的所有题目

永远少年_3 2个月前

#include[HTML_REMOVED]
#include[HTML_REMOVED]
using namespace std;
int main(void) {
int t; cin >> t; string s1; string s2;
for (int i = 0; i < t; i++)
{
cin >> s1; cin >> s2;
if (s1 == s2)cout << “Tie”;
else if (s1 == “Gun” && s2 == “Bear” || s1 == “Bear” && s2 == “Hunter” || s1 == “Hunter” && s2 == “Gun”)cout << “Player1”;
else cout << “Player2”;
if (i < t - 1)cout << endl;
}
}

codmQAQ 5个月前

？

#include <iostream>
#include <cstring>
#include <cstdio>

using namespace std;

int main()
{
    int t;
    cin>>t;
    string x,y;
    while(t--)
    {
        cin>>x>>y;
        if(x==y) cout<<"Tie"<<endl;
        if(x=="Hunter" && y=="Gun") cout<<"Player1"<<endl;
        if(x=="Hunter" && y=="Bear") cout<<"Player2"<<endl;
        if(x=="Gun" && y=="Hunter") cout<<"Player2"<<endl;
        if(x=="Gun" && y=="Bear") cout<<"Player1"<<endl;
        if(x=="Bear" && y=="Hunter") cout<<"Player1"<<endl;
        if(x=="Bear" && y=="Gun") cout<<"Player2"<<endl;
    }
    return 0;
}

小睡几年 2023-05-12 16:56

Orz

蛊惑角 6个月前

#include[HTML_REMOVED]
using namespace std;
int main() {
string a,b;
int n;
cin>>n;
while(n–){
cin>>a>>b;
if(a==”Hunter”){
if(b==”Gun”) cout<<”Player1”<<endl;
else if(b==”Bear”) cout<<”Player2”<<endl;
else cout<<”Tie”<<endl;
}
else if(a==”Gun”){
if(b==”Bear”) cout<<”Player1”<<endl;
else if(b==”Hunter”) cout<<”Player2”<<endl;
else cout<<”Tie”<<endl;
}
else if(a==”Bear”){
if(b==”Hunter”) cout<<”Player1”<<endl;
else if(b==”Gun”) cout<<”Player2”<<endl;
else cout<<”Tie”<<endl;
}
}
return 0;
}