a&1 为当前为当前a末位是否为1

#include<iostream>

const int N = 1e6+10;


int main()
{
    int n;
    scanf("%d",&n);

    while(n--)
    {
        int res = 0,num;
        scanf("%d",&num);
        while(num>0)
        {
            res+= num&1;
            num=num>>1;
        }
        printf("%d ",res);
    }
}