C++代码

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string>
#include <sstream>
using namespace std;

int x, y, z;
string s;
int date[3];
int cnt[100000000];
bool judge_date(int year, int month, int day)
{
    int k[13] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    if(month < 1 || month > 12) return false;
    if(day < 1 || day > k[month]) return false;
    if(!((year % 100 != 0 && year % 4 == 0) || year % 400 == 0) && month == 2)
        if(day > 28) return false;
    return true;
}
int main()
{
    int year, month, day;
    scanf("%d/%d/%d", &x, &y, &z);
    if(x >= 60 && x <= 99) date[0] = 19*1000000 + x * 10000 + y * 100 + z;
    else date[0] = 20*1000000 + x * 10000 + y * 100 + z;
    if(z >= 60 && z <= 99) date[1] = 19*1000000 + z * 10000 + x * 100 + y;
    else date[1] = 20*1000000 + z * 10000 + x * 100 + y;
    if(z >= 60 && z <= 99) date[2] = 19*1000000 + z * 10000 + y * 100 + x;
    else date[2] = 20*1000000 + z * 10000 + y * 100 + x;

    sort(date, date + 3);
    for(int i = 0; i < 3; i ++)
    {
        if(cnt[date[i]] == 0){
            year = date[i] / 10000;
            month = (date[i] / 100) % 100;
            day = date[i] % 100;
            if(judge_date(year, month, day))
                printf("%04d-%02d-%02d\n", year, month, day);
        }
        cnt[date[i]] ++;
    }

    return 0;
}
//枚举三种可能的排列，并从小到大排列，依次判断是否符合日期的条件