AcWing 849. Dijkstra求最短路 I
原题链接
简单
作者:
haicyang
,
2020-08-23 03:17:13
,
所有人可见
,
阅读 479
#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N=510;
int n, m;
int g[N][N];
int dist[N];
bool st[N];
int dijkstra()
{
memset(dist, 0x3f, sizeof dist);
dist[1]=0;
for (int i=0; i<n; i++) {
int t=-1;
for (int j=1; j<=n; j++) {
if (!st[j] && (t==-1 || dist[t]>dist[j]))
t=j;
}
st[t]=true;
for (int j=1; j<=n; j++) {
dist[j]=min(dist[j], dist[t]+g[t][j]);
}
}
if (dist[n]==0x3f3f3f3f) return -1;
return dist[n];
}
int main()
{
scanf("%d%d", &n, &m);
memset(g, 0x3f, sizeof g);
for (int i=0; i<m; i++) {
int a, b, c;
scanf("%d%d%d", &a, &b, &c);
g[a][b]=min(g[a][b], c);
}
int res=dijkstra();
printf("%d\n", res);
}