AcWing 792. 高精度减法
原题链接
简单
作者:
NeonSean
,
2020-08-17 16:30:45
,
所有人可见
,
阅读 308
#include <iostream>
#include <vector>
using namespace std;
const int N = 1e6 + 10;
bool cmp(vector<int> &A, vector<int> &B) {
if(A.size() != B.size()) return A.size() > B.size();
for (int i = A.size() - 1; i >= 0; i--) {
if(A[i] != B[i]) return A[i] > B[i];
}
return A[0] >= B[0];
}
vector<int> sub(vector<int> &A, vector<int> &B) {
vector<int> C;
int t = 0;
for (int i = 0; i < A.size(); i++) {
t = A[i]- t;
if (i < B.size()) t -= B[i];
C.push_back((t + 10) % 10);
if (t < 0) t = 1;
else t = 0;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
int main() {
string a, b;
vector<int> A, B, res;
cin >> a >> b;
for (int i = a.size() - 1; i >= 0; i--) A.push_back(a[i] - '0');
for (int i = b.size() - 1; i >= 0; i--) B.push_back(b[i] - '0');
if (cmp(A, B)) {
res = sub(A, B);
}else {
res = sub(B, A);
cout << '-';
}
for (int i = res.size() - 1; i >= 0; i--) cout << res[i];
cout << endl;
return 0;
}