把每一个序列映射在二进制下

#include <iostream>
#include <cmath>
using namespace std;
typedef long long ll;
int main(){
    ll n, k;   cin >> n >> k;
    ll res = 0;
    for(int i = 0; i < 32; i ++ ){
        if(k >> i & 1)  res += ll(pow(n, i));
    }
    cout << res << endl;
    return 0;
}