一、Y总先让下标减一，后面求坐标就很简单

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int w,m,n;
    int x1,y1,x2,y2;
    cin>>w>>n>>m;
    m--;n--;
    x1=n/w;
    x2=m/w;
    y1=n%w;
    y2=m%w;
    if(x1%2)
        y1=w-1-y1;
    if(x2%2)
        y2=w-1-y2;

    int ans=abs(x1-x2)+abs(y1-y2);
    cout<<ans<<endl;
    return 0;
}

我没有将下标减一 硬找规律 很难写

#include<bits/stdc++.h>
using namespace std;
int w, a, b;
int main()
{
    int row1, row2, line1, line2;
    cin >> w >> a >> b;
    int num = a % w;
    if (a % w == 0) {
        line1 = a / w;
        if ((a / w) % 2 == 0) {
            row1 = num + 1;
        }
        else {
            row1 = w - num;
        }
    }
    else {
        line1 = a / w + 1;
        if ((a / w) % 2 == 0)
            row1 = num;
        else row1 = w - num + 1;
    }
    int num1 = b % w;
    if (b % w == 0) {
        line2 = b / w;
        if ((b / w) % 2 == 0) {
            row2 = num1 + 1;
        }
        else {
            row2 = w - num1;
        }
    }
    else {
        line2 = b / w + 1;
        if ((b / w) % 2 == 0)
            row2 = num1;
        else row2 = w - num1 + 1;
    }
    int ans = abs(row1 - row2) + abs(line1 - line2);
    cout << ans << endl;

    return 0;
}