AcWing 36. 合并两个排序的链表
原题链接
简单
作者:
adamXu
,
2020-09-26 12:50:56
,
所有人可见
,
阅读 365
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* merge(ListNode* l1, ListNode* l2) {
//归并的思路
auto dummy = new ListNode(-1);
auto cur = dummy;
while(l1 && l2){ //注意不是!l1 && !l2
if(l1->val < l2->val)
{
cur->next = l1;
l1 = l1->next;
}
else
{
cur->next = l2;
l2 = l2->next;
}
cur = cur-> next;
}
cur->next = (l1 != nullptr ? l1 : l2);
return dummy->next;
}
};