题目描述

//纯暴力

C++ 代码

#include<iostream>
using namespace std;
int main() {
    string s1;
    while (cin >> s1) {
        if (s1 != ".") {
            int l = s1.length(),sum=0;
            for (int i = 1; i <=l/2; i++) {//最多遍历到一半的位置
                if (s1.substr(i, i) == s1.substr(0, i)) {//如果从0到当前长度的子串与下一个相等长度的子串相等

                    sum = (l / (i));
                    for (int j = 0; j < l - i; j+=i) {//遍历字符串，若存在不等的子串则说明找到的子串并不是正确的
                        if (s1.substr(0, i) == s1.substr(j + i, i))continue;
                        else {
                            sum = 0; break;
                        }
                    }
                }
                    if (sum) {
                        cout << sum << endl;
                        break;
                    }

                //cout << s1.substr(0, i) << " != " << s1.substr(i, i)<<endl;
            }
            if (!sum)cout <<1<<endl;
        }
        else break;
    }
    return 0;
}