要求：输出矩阵
套路：找坐标i,j和元素大小的关系

#include <iostream>
#include <cmath>
using namespace std;

int main(){
    int N;
    while (cin >> N,N){
        for (int i = 0;i < N;i++){
            for (int j = 0; j < N;j++){
                int ABS = abs(i-j);
                cout << 1 + ABS << " " ;
            }
            cout << endl;
        }
        cout << endl;
    }
    return 0;
}