AcWing 849. Dijkstra求最短路 I
原题链接
简单
作者:
在月球_0
,
2024-10-28 18:35:48
,
所有人可见
,
阅读 1
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int N = 510;
int g[N][N];
long long dist[N];
bool st[N];
int n,m;
long long dijkstra()
{
memset(dist, 0x3f,sizeof dist);
dist[1] = 0;
for(int i = 0;i < n;i++)
{
int t = -1;
for(int j = 1;j <= n;j++)
{
if(!st[j] && (t == -1 || dist[t] > dist[j])) t = j;
}
st[t] = true;
for(int j = 1;j <= n;j++)
{
dist[j] = min(dist[j],dist[t] + g[t][j]);
}
}
if(dist[n] > 0x3f3f3f) return -1;
return dist[n];
}
int main()
{
scanf("%d%d",&n,&m);
memset(g,0x3f,sizeof g);
while(m--)
{
int x,y,z;
scanf("%d%d%d",&x,&y,&z);
g[x][y] = min(g[x][y],z);
}
long long t = dijkstra();
printf("%d\n",t);
return 0;
}