题目描述

blablabla

样例

#include <iostream>

using namespace std;

int main(){
    int N;
    int denomination[7] = {100,50, 20, 10, 5, 2, 1};
    int count[7] = {};
    cin >> N;
    printf("%d\n", N);
    for (int i = 0; i < 7; i++){
        count[i] = N/denomination[i];
        N = N % denomination[i];
    }


    for (int j = 0; j < 7; j++){
        printf("%d nota(s) de R$ %d,00\n", count[j], denomination[j]);
    }

    return 0;
}

算法1

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla

算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla