AcWing 36. 合并两个排序的链表
原题链接
简单
作者:
Saber__
,
2024-11-03 17:07:06
,
所有人可见
,
阅读 2
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* merge(ListNode* l1, ListNode* l2) {
auto head = new ListNode(-1), tail = head;
while(l1 && l2)
{
if(l1->val < l2->val)
{
tail = tail->next = l1;
l1 = l1->next;
}
else
{
tail = tail->next = l2;
l2 = l2->next;
}
}
if(l1) tail->next = l1;
else if(l2) tail->next = l2;
return head->next;
}
};