题目描述

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样例

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#include <iostream>
using namespace std;
#define int long long
const int N = 100010;
int a[N],b[N];
int n,m;
signed main()
{
   cin >> n >> m;
   for(int i = 1;i <= n;i ++) cin >> a[i];
   for(int i = 1;i <= m;i ++) cin >> b[i];
   int i = 1,j = 1;
   while(i <= n && j <= m){
      if(a[i] == b[j]) i ++,j ++;
      else j ++;
   }
   if(i == n+1){
      cout << "Yes" << endl;
   }else{
      cout << "No" << endl;
   }
    return 0;
}

算法1

(暴力枚举) $O(n^2)$

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时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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