题目描述

笑死啦有的是力气和手段

#include <iostream>
#include <cstdio>
using namespace std;
int main(){
    int n,a,b,c,d,e,f,g;
    cin>>n;
    a=n/100;
    b=n%100/50;
    c=(n-a*100-b*50)/20;
    d=(n-a*100-b*50-c*20)/10;
    e=(n-a*100-b*50-c*20-d*10)/5;
    f=(n-a*100-b*50-c*20-d*10-e*5)/2;
    g=n-a*100-b*50-c*20-d*10-e*5-f*2;
    printf("%d\n%d nota(s) de R$ 100,00\n%d nota(s) de R$ 50,00\n%d nota(s) de R$ 20,00\n%d nota(s) de R$ 10,00\n%d nota(s) de R$ 5,00\n%d nota(s) de R$ 2,00\n%d nota(s) de R$ 1,00\n",n,a,b,c,d,e,f,g);
    return 0;
}

循环的苗头

blablabla

时间复杂度

参考文献

C++ 代码

#include <iostream>
#include <cstdio>
using namespace std;
int main(){
    int n,a,b,c,d,e,f,g;
    cin>>n;
    a=n/100;
    b=n%100/50;
    c=n%100%50/20;
    d=n%100%50%20/10;
    e=n%100%50%20%10/5;
    f=n%100%50%20%10%5/2;
    g=n%100%50%20%10%5%2;
    printf("%d\n%d nota(s) de R$ 100,00\n%d nota(s) de R$ 50,00\n%d nota(s) de R$ 20,00\n%d nota(s) de R$ 10,00\n%d nota(s) de R$ 5,00\n%d nota(s) de R$ 2,00\n%d nota(s) de R$ 1,00\n",n,a,b,c,d,e,f,g);
    return 0;
}

循环和数组

blablabla

时间复杂度

参考文献

C++ 代码

#include <iostream>
#include <cstdio>
using namespace std;
int main(){
    int mianzhi[7]={100,50,20,10,5,2,1};
    int n,i;
    cin>>n;
    printf("%d\n",n);
    for(i=0;i<=6;i++){
        printf("%d nota(s) de R$ %d,00\n",n/mianzhi[i],mianzhi[i]);
        n%=mianzhi[i];
    }
    return 0;
}