#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int a,s,d,f,g,h,j;
    a=n/100;
    s=(n-100*a)/50;
    d=(n-100*a-50*s)/20;
    f=(n-100*a-50*s-20*d)/10;
    g=(n-100*a-50*s-20*d-10*f)/5;
    h=(n-100*a-50*s-20*d-10*f-5*g)/2;
    j=(n-100*a-50*s-20*d-10*f-5*g-2*h);
    cout<<n<<endl;
    cout<<a<<" nota(s) de R$ 100,00"<<endl;
    cout<<s<<" nota(s) de R$ 50,00"<<endl;
    cout<<d<<" nota(s) de R$ 20,00"<<endl;
    cout<<f<<" nota(s) de R$ 10,00"<<endl;
    cout<<g<<" nota(s) de R$ 5,00"<<endl;
    cout<<h<<" nota(s) de R$ 2,00"<<endl;
    cout<<j<<" nota(s) de R$ 1,00"<<endl;
    return 0;
}

很暴力很麻烦，可以直接用数组＋循环来解决