题目描述

要注意使用double，输出要换行

样例

#include<iostream>
#include<iomanip>
using namespace std;
int main() {
    double A, B, C;
    cin >> A >> B >> C;
    const double pi = 3.14159;
    double sanjiao = 1 / 2.0 * A * C;
    double yuan = pi * C * C;
    double tixing = (A + B) * C * 1 / 2.0;
    double zhengfang = B * B;
    double changfang = A * B;
    cout << fixed << setprecision(3) << "TRIANGULO: " << sanjiao << endl;
    cout << fixed << setprecision(3) << "CIRCULO: " << yuan << endl;
    cout << fixed << setprecision(3) << "TRAPEZIO: " << tixing << endl;
    cout << fixed << setprecision(3) << "QUADRADO: " << zhengfang << endl;
    cout << fixed << setprecision(3) << "RETANGULO: " << changfang << endl;
    return 0;
}

算法1

(暴力枚举) $O(n^2)$

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时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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