题目描述

%的输出需要两个

样例

#include<bits/stdc++.h>
using namespace std;
int main(){
    double a;
    cin>>a;
    if(a>=0&&a<=400){
        printf("Novo salario: %.2lf\n",a*(1+0.15));
        printf("Reajuste ganho: %.2lf\n",a*0.15);
        printf("Em percentual: 15 %%\n");
    }else if(a>400&&a<=800){
        printf("Novo salario: %.2lf\n",a*(1+0.12));
        printf("Reajuste ganho: %.2lf\n",a*0.12);
        printf("Em percentual: 12 %%\n");
    }else if(a>800&&a<=1200){
        printf("Novo salario: %.2lf\n",a*(1+0.10));
        printf("Reajuste ganho: %.2lf\n",a*0.10);
        printf("Em percentual: 10 %%\n");
    }else if(a>1200&&a<=2000){
        printf("Novo salario: %.2lf\n",a*(1+0.07));
        printf("Reajuste ganho: %.2lf\n",a*0.07);
        printf("Em percentual: 7 %%\n");
    }else{
        printf("Novo salario: %.2lf\n",a*(1+0.04));
        printf("Reajuste ganho: %.2lf\n",a*0.04);
        printf("Em percentual: 4 %%\n");
    }
    return 0;

}

算法1

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla