枚举日期范围判断是否合法，合法就看看否是符合三种组合要求

import java.util.*;

public class Main {
    static int[] days = {0, 31, 30, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        String[] s = sc.nextLine().split("/");

        int a = toInt(s[0]), b = toInt(s[1]), c = toInt(s[2]);

        for (int i = 19600101; i <= 20581231; i++) {
            int year = i / 10000, mouth = i % 10000 / 100, day = i % 100;
            if (cheek(year, mouth, day)) {
                if (year % 100 == a && mouth == b && day == c || mouth == a && day == b && year % 100 == c || day == a && mouth == b && year % 100 == c) {
                    System.out.printf("%d-%02d-%02d\n", year, mouth, day);
                    //%02d占2位不足高位补0
                }
            }
        }
    }

    static boolean cheek(int year, int mouth, int day) {
        if (mouth > 12 || mouth == 0) return false;
        if (day == 0) return false;
        if (mouth != 2 && day > days[mouth]) return false;
        if (mouth == 2) {
            boolean flag = year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
            int t = flag ? 29 : 28;
            if (day > t) return false;
        }
        return true;
    }

    static int toInt(String s) {
        return Integer.parseInt(s);
    }
}