#由1构成的直线是i=j (y=x)       => abs(i-j)=0  => 0+1=1
 #由2构成的直线是i=j+1 和 i=j-1 => abs(i-j)=1  => 1+1=2
 #... 
 #由k 构成的直线是i=j+b和i=j-b   => abs(i-j)=b  => b+1=b+1=k
 # 
while 1:
    try:
        n=int(input())
        if n != 0:
            li=[]
            for i in range(n):
                st=[]
                for j in range(n):
                    st.append(1+abs(i-j))
                li.append(st)
            #print(li)
            for i in li:
                for j in i:
                    print(j,end=' ')
                print('')

            print('')
    except:
        break