题目描述

求一个字符串中最长的连续出现的字符，输出该字符及其出现次数，字符串中无空白字符（空格、回车和tab），如果这样的字符不止一个，则输出第一个。

C++ 代码

#include <iostream>
#include <string>
using namespace std;

int main() {
    int n;
    cin >> n;
    string s;
    for (int i = 0; i < n; ++i) {
        cin >> s;
        if (s.empty()) continue;
        char max_char = s[0];
        int max_count = 1;
        int current_count = 1;
        for (size_t j = 1; j < s.size(); ++j) {
            if (s[j] == s[j - 1]) {
                ++current_count;
            } else {
                if (current_count > max_count) {
                    max_count = current_count;
                    max_char = s[j - 1];
                }
                current_count = 1;
            }
        }
        // 处理字符串末尾的情况
        if (current_count > max_count) {
            max_count = current_count;
            max_char = s[s.size() - 1];
        }
        cout << max_char << " " << max_count << endl;
    }
    return 0;
}