#include<iostream>

using namespace std;

const int N = 10010;
int n,m,a[N];
int ans = 0;

int main()
{
    cin>>n>>m;
    for(int i = 1; i<=n; i++)
    {
        int x; cin>>x;
        a[i] = a[i-1]+x;
    }
    //枚举所有l,r的值
    for(int l = 1; l<=n; l++)
    {
        for(int r = l; r<=n; r++)
        {
            if(a[r]-a[l-1]<=m) ans++;
            else break;
        }
    }
    cout<<ans;
    return 0;
}