//本题学习下异或操作: x ^ 1

#include <iostream>

using namespace std;

int main(){

    int x,i,j;
    cin >> x >> i >> j;
    int a = (x >> i)&1 , b = (x >> j)&1;   //取出二进制下的第i位
    if(a == b){
        cout << x << endl;
    }else{
        x = x^(1<<i);   //将二进制下的第i位取反：用异或实现
        x = x^(1<<j);
        cout << x << endl;
    }

    return 0;
}