方法一 : 把 得分表 存到 二维数组中（只统计加分） 后面直接查表；

#include <iostream>
using namespace std;

const int N = 210;
int n, na, nb;
int a[N], b[N];
int res_a, res_b;
int cal[5][5] = {
0, 0, 1, 1, 0,
1, 0, 0, 1, 0,
0, 1, 0, 0, 1,
0, 0, 1, 0, 1,
1, 1, 0, 0, 0};

int main()
{
    cin >> n >> na >> nb;
    for(int i = 0; i < na; ++i) cin >> a[i];
    for(int i = 0; i < nb; ++i) cin >> b[i];

    int i = 0;
    while (n --){
        res_a = cal[a[i % na]][b[i % nb]];
        res_b = cal[b[i % nb]][b[i % na]];
        i ++;
    }
    cout << res_a << " " << res_b << endl;
    return 0;
}

方法二： 直接写

#include <iostream>

using namespace std;
const int N = 200;
int n, a, b;
int a1[N],a2[N];
int A, B;

void check()
{
    for(int i = 0; i < n; ++i)
    {

        if(a1[i % a] == 0 && a2[i % b] == 1) {B ++;continue;}
        if(a1[i % a] == 0 && a2[i % b] == 2){A ++;continue;}
        if(a1[i % a] == 0 && a2[i % b] == 3){A ++;continue;}
        if(a1[i % a] == 0 && a2[i % b] == 4){B ++;continue;}



        if(a1[i % a] == 1 && a2[i % b] == 0){A ++;continue;}
        if(a1[i % a] == 1 && a2[i % b] == 2){B ++;continue;}
        if(a1[i % a] == 1 && a2[i % b] == 3){A ++;continue;}
        if(a1[i % a] == 1 && a2[i % b] == 4){B ++;continue;}


        if(a1[i % a] == 2 && a2[i % b] == 0){B ++;continue;}
        if(a1[i % a] == 2 && a2[i % b] == 1){A ++;continue;}
        if(a1[i % a] == 2 && a2[i % b] == 3){B ++;continue;}
        if(a1[i % a] == 2 && a2[i % b] == 4){A ++;continue;}



        if(a1[i % a] == 3 && a2[i % b] == 0){B ++;continue;}
        if(a1[i % a] == 3 && a2[i % b] == 1){B ++;continue;}
        if(a1[i % a] == 3 && a2[i % b] == 2){A ++;continue;}
        if(a1[i % a] == 3 && a2[i % b] == 4){A ++;continue;}



        if(a1[i % a] == 4 && a2[i % b] == 0){A++;continue;}
        if(a1[i % a] == 4 && a2[i % b] == 1){A++;continue;}
        if(a1[i % a] == 4 && a2[i % b] == 2){B++;continue;}
        if(a1[i % a] == 4 && a2[i % b] == 3){B++;continue;}
    }
}
int main()
{
    cin >> n >> a >> b;

    for(int i = 0; i <a; ++i) cin >> a1[i];
    for(int i = 0; i < b; ++i) cin >> a2[i];


     check();


    cout <<A << " " << B<< endl;
    return 0;
}