AcWing 36. 合并两个排序的链表
原题链接
简单
作者:
小轩喵灬
,
2025-01-10 09:54:08
,
所有人可见
,
阅读 1
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode merge(ListNode l1, ListNode l2) {
ListNode head = new ListNode(-1);
ListNode cur = head;
while(l1 != null && l2 != null) {
if (l1.val <= l2.val) {
cur.next = l1;
l1 = l1.next;
} else {
cur.next = l2;
l2 = l2.next;
}
cur = cur.next;
}
if (l1 != null) {
cur.next = l1;
}
if (l2 != null) {
cur.next = l2;
}
return head.next;
}
}