AcWing 93. 递归实现组合型枚举
原题链接
简单
作者:
贩卖日落_02
,
2025-04-04 13:43:15
· 河南
,
所有人可见
,
阅读 1
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 30;
int n, m;
int way[N];
void dfs(int u, int start)
{
if (u + n - start < m) return;
if (u == m + 1)
{
for (int i = 1; i <= m; i ++ ) printf("%d ", way[i]);
puts("");
return;
}
for (int i = start; i <= n; i ++ )
{
way[u] = i;
dfs(u + 1, i + 1);
way[u] = 0;
}
}
int main()
{
scanf("%d%d", &n, &m);
dfs(1, 1);
return 0;
}