法1：对整个字符串进行判断

#include<iostream>

using namespace std;

int main()
{
    string s;
    while(cin >> s, s != ".")
    {
        bool flag;
        int len = s.length();
        for(int i = 1; i <= len; i ++ )
            if(len % i == 0)
            {
                flag = true;
                for(int j = 0; j < len; j ++ )
                    if(s[j] != s[j % i])
                    {
                        flag = false;
                        break;
                    }
                if(flag)
                {
                    cout << len / i << endl;
                    break;
                }
            }
        // cout << endl;
    }
    return 0;
}

法2：用substr提取子串，拼接成新字符串进行比较

#include<iostream>

using namespace std;

int main()
{
    string s;
    while(cin >> s, s != ".")
    {
        int len = s.length();
        for(int i = 1; i <= len; i ++ )
            if(len % i == 0)
            {
                int num = len / i;
                string t = s.substr(0, i);
                string t2;
                while(t2.length() < len)
                    t2 += t;
                if(t2 == s)
                {
                    cout << num << endl;
                    break;
                }
            }
    }
    return 0;
}