题目描述
Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes: val and next. val is the value of the current node, and next is a pointer/reference to the next node. If you want to use the doubly linked list, you will need one more attribute prev to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement these functions in your linked list class:
get(index) : Get the value of the index-th node in the linked list. If the index is invalid, return -1.
addAtHead(val) : Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.
addAtTail(val) : Append a node of value val to the last element of the linked list.
addAtIndex(index, val) : Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. If index is negative, the node will be inserted at the head of the list.
deleteAtIndex(index) : Delete the index-th node in the linked list, if the index is valid.
样例
Example:
MyLinkedList linkedList = new MyLinkedList();
linkedList.addAtHead(1);
linkedList.addAtTail(3);
linkedList.addAtIndex(1, 2); // linked list becomes 1->2->3
linkedList.get(1); // returns 2
linkedList.deleteAtIndex(1); // now the linked list is 1->3
linkedList.get(1); // returns 3
Note:
All values will be in the range of [1, 1000].
The number of operations will be in the range of [1, 1000].
Please do not use the built-in LinkedList library.
很坑的题,只过了60个测试集,最后一个测试集居然可以出现-1的index跟题目意思有点冲突了
C++ 代码
class MyLinkedList {
public:
/** Initialize your data structure here. */
MyLinkedList():head(nullptr),size(0) {
}
/** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */
int get(int index) {
if(index>=size||index<0){
return -1;
}
else{
Node *cur=head;
while(index--){
cur=cur->next;
}
return cur->val;
}
}
/** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */
void addAtHead(int val) {
Node *node=new Node(val);
node->next=head;
head=node;
size++;
}
/** Append a node of value val to the last element of the linked list. */
void addAtTail(int val) {
Node *node=new Node(val);
Node *cur=head;
for(int i=0;i<size-1;i++){
cur=cur->next;
}
cur->next=node;
size++;
}
/** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */
void addAtIndex(int index, int val) {
if(index<0||index>size)
return;
if(index==0)
{
addAtHead(val);
return;
}
Node *node=new Node(val);
Node *cur=head->next;
Node *prev=head;
for(int i=0;i<index-1;i++){
prev=cur;
cur=cur->next;
}
prev->next=node;
node->next=cur;
size++;
}
/** Delete the index-th node in the linked list, if the index is valid. */
void deleteAtIndex(int index) {
if(index<0||index>=size)
return;
if(index==0)
{
head=head->next;
size--;
return;
}
Node *cur=head->next;
Node *prev=head;
for(int i=0;i<index-1;i++){
prev=cur;
cur=cur->next;
}
prev->next=prev->next->next;
size--;
}
private:
struct Node{
public:
int val;
Node *next;
Node():val(0),next(nullptr){}
Node(int _val):val(_val),next(nullptr){}
};
Node *head;
int size;
};
/**
* Your MyLinkedList object will be instantiated and called as such:
* MyLinkedList* obj = new MyLinkedList();
* int param_1 = obj->get(index);
* obj->addAtHead(val);
* obj->addAtTail(val);
* obj->addAtIndex(index,val);
* obj->deleteAtIndex(index);
*/
提交的时候提示插入尾结点处
Line 29: Char 19: runtime error: member access within null pointer of type 'struct ListNode' (solution.cpp)
大神能能解答一下吗,万分感谢。中秋节快乐!