AcWing 29. 删除链表中重复的节点
原题链接
中等
作者:
STU756
,
2021-01-20 18:10:55
,
所有人可见
,
阅读 294
//Java
class Solution {
public ListNode deleteDuplication(ListNode head) {
ListNode dummy = new ListNode(-1);
dummy.next = head;
ListNode p = dummy;
while(p.next != null) {
ListNode q = p.next;
while(q!=null && (p.next.val == q.val)) q = q.next;
if(p.next.next == q) p = p.next;
else p.next = q;
}
return dummy.next;
}
}
//C++
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplication(ListNode* head) {
ListNode* dummy = new ListNode(-1);
dummy->next = head;
ListNode* p = dummy;
while(p->next) {
ListNode* q = p->next;
while(q && p->next->val == q->val) q = q->next;
if(p->next->next == q) p = p->next;
else p->next = q;
}
return dummy->next;
}
};